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Q7) A milkman sold two of his buffaloes for Rs.20,000 each. On one he made a gain of 5% and on the other a loss of 10%. Find his overall gain or loss. (Hint: Find CP of each)

Solution:

S.P. of each buffalo = Rs.20,000

S.P. of two buffaloes = 20000 x 2

= Rs. 40,000

One buffalo is sold at 5% gain.

Let C.P. be Rs.100, then S.P. = 100 + 5

= Rs.105

\because When S.P. is Rs.105, then C.P. = Rs.100

\therefore When S.P. is Rs.1, then C.P. = \frac{100}{105}

\therefore When S.P. is Rs.20,000, then C.P.

= \frac{100}{105}\times20000=Rs.\ 19,047.62

Another buffalo is sold at 10% loss.

Let C.P. be Rs.100, then S.P. = 100 – 10

= Rs.90

\because When S.P. is Rs.90, then C.P. = Rs.100

\therefore When S.P. is Rs.1, then C.P. = \frac{100}{90}

\therefore When S.P. is Rs.20,000, then C.P.

= \frac{100}{90}\times20000=Rs.\ 22,222.22

Total C.P. = Rs.19,047.62 + Rs.22,222.22

= Rs.41,269.84

Since C.P. >S.P.

Therefore here it is a loss.

Loss = C.P. – S.P.

= Rs.41,269.84 – Rs. 40,000.00 = Rs.1,269.84

Solution:

S.P. of each buffalo = Rs.20,000

S.P. of two buffaloes = 20000 x 2

= Rs. 40,000

One buffalo is sold at 5% gain.

Let C.P. be Rs.100, then S.P. = 100 + 5

= Rs.105

\because When S.P. is Rs.105, then C.P. = Rs.100

\therefore When S.P. is Rs.1, then C.P. = \frac{100}{105}

\therefore When S.P. is Rs.20,000, then C.P.

= \frac{100}{105}\times20000=Rs.\ 19,047.62

Another buffalo is sold at 10% loss.

Let C.P. be Rs.100, then S.P. = 100 – 10

= Rs.90

\because When S.P. is Rs.90, then C.P. = Rs.100

\therefore When S.P. is Rs.1, then C.P. = \frac{100}{90}

\therefore When S.P. is Rs.20,000, then C.P.

= \frac{100}{90}\times20000=Rs.\ 22,222.22

Total C.P. = Rs.19,047.62 + Rs.22,222.22

= Rs.41,269.84

Since C.P. >S.P.

Therefore here it is a loss.

Loss = C.P. – S.P.

= Rs.41,269.84 – Rs. 40,000.00 = Rs.1,269.84

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